In the given figure, O is the centre of a circle, AB is a side of regular octagon and AC is a side of regular hexagon. Find :
(i) ∠AOB (ii) ∠AOC (iii) ∠BOC.
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Answer:
∠AOB = 60°, ∠BOC = 45° , ∠ABC = 105°, ∠ACB = 30°
Step-by-step explanation:
Regular hexagon which is inscribed in circle, will have sides equal to radius (r) of circle.
∴ AB = OA = OB = OC = r
Δ AOB is equilateral triangle.
∴ ∠AOB = 60°
BC is a side of octagon,
∴ ∠BOC = 360 / 8 = 45°
∠BAC = ∠BOC / 2 = 45/2 = 22.5° Reason - Angle subtended in arc is twice the angle subtended at circumference.
∠ACB = ∠BOA / 2 = 60/2 = 30° Reason - Angle subtended in arc is twice the angle subtended at circumference.
∠ABC = ∠ABO + ∠OBC = 60° + 45° = 105°
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