In the given figure, O is the centre of a circle
and AOC = 140°. Find ABC.
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Step-by-step explanation:
Given that ∠AOC=140
∘
∠ABC=
2
140
=70
∘
Because WKT angle made by a chord aa any point on the circle is half the angle made by it at the center
In △AOC
AO=CO=radius
⟹∠OAC=∠OCA
And
2∠OCA=180−∠AOC
⟹∠OCA=
2
40
=20=∠OAC
In △ABC
AB=BC
⟹∠BAC=∠BCA
And
2∠BAC=180−∠ABC
⟹∠BAC=55
∠OAB=∠CAB−∠CAO=55–20=35
∘
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