Question

in the given figure,O is the centre of a circle,AOB= 90, BOC=120, what the measure of ABC​

Answer 1

Step-by-step explanation:

Angle ABC=Angle AOB + Angle BOC

=90° +120°

=210°

Answer 2

The measure of ABC​ is 75°

Step-by-step explanation:

given that

$\angle AOB = 90\\\angle BOC = 120$

let us find the angle AOC

$\angle AOC = 360 - \angle AOB - \angle BOC \\\angle AOC = 360 - 90-120\\\angle AOC = 150$

Then

m(arc AC) = 150°

using inscribed angled theorem

$m(\angle ABC ) = 0.5 \times m (arc AC) \\m(\angle ABC ) = 0.5 \times 150\\\angle ABC = 75$

hence ,

$\angle ABC$ = 75°

#Learn more:

In the given figure o is the centre of the circle and AOB=120 AEB =?

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