Question

In the given figure , O is the centre of a circle . If ∆ ABC = 56° , Find ∆ ACB . Also , find , ∆ CBD if ∆ BCD = 44°​

Answer 1

Answer:

ABCP is a cyclic quadrilateral

.•. angle APC = angle CBD

angle APC = ½angle AOC

=> angle APC = 50°

•.• angle APC = angle CBD

=> angle CBD = 50°