In the given figure, O is the centre of a circle. If angle AOD =140 and angle CAB = 50 , calculate
1. angle EDB 2. angle EBD
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Answer:
answer for 1 is 50°
Step-by-step explanation:
ABCD is a cyclic quadrilatral and in a cyclic quad opp angles are supplementary
so 50° + angle cod = 180
hence cod = 180 - 50 = 130
now angle cod and angle ebd are supplementary as they form a straight line
so 130 + angle edb = 180
angle edb = 180 - 130 = 50°
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Answer:
r u studying 9 th class A section?
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