Math, asked by neha2468, 3 months ago

In the given figure. O is the centre of a circle. If angleOAB-40° and C is a point on the
circle, then find angleACB.

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Answers

Answered by Anonymous
2

Answer❀✿°᭄

Let Z be the number

Z = 13x + 11 where x is the quotient when Z is divided by 13

Z = 17y + 9 where y is the quotient when Z is divided by 17

13x + 11 = 17y + 9

13x + 2 = 17y since x and y are quotients they should be whole numbers . Since y has to be a whole number the left hand side should be multiple of 17

The least possible value of x satisfying the condition is 9 and y will be 7

The answer is 13*9 + 11 = 128 or it is 17*7 + 9 = 128

This is the least number possible. There will be multiple answers and will increase in multiples 17*13 = 221 like 349 , 570, etc

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Answered by bhagadkarvaidehi2005
4

Answer:

50

Step-by-step explanation:

angle OAB-40

then , angle OBA=40

since , if two sides of a triangle is equal then the corresponding angles are also equal

Now , by angle sum property

angle AOB =100

and thus angle ACB =50

because angle ACB is always half of angle AOB

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