Question

In the given figure, O is the centre of a circle of radius r cm, OP and OQ are perpendiculars to AB and CD respectively and PQ=1. If AB ll CD, AB=6cm and CD=8cm, find the diameter of the circle

Answer 1

in triangle APQ we have,
AQ sq = PQ sq + AP sq
AQ sq = 3 sq + 1 sq
AQ = √10
diameter = 2r

diameter is = 2 unde root 10 or ( 2√10 ) cm .

Answer 2

heya...

here is you answer..