Question

In the given figure,O is the centre of a circle passing through ABC, Angle PAB=Angle BAC. Show that PQ is a tangent to the circle at A​

Answer 1

Answer:

Something is missing in the given question.

Step-by-step explanation:

According to angle PAB is equal to angle BAC

Therefore, $\angle$PAB =

and OA = OB                   [ OA and OB is the radius of the circle]

∴  $\angle$ABO =

From the triangle ABO

$\angle A+\angle B+\angle O=180^{0}$                   [∵$\angle A=\angle B$]

$\angle O=90^{0}$