Question

In the given figure, O is the centre of a circle,
PQ is a side of a regular octagon
and QR is a side of regular hexagon. Find :
i) ∠POQ ii)∠QOR iii)∠POR​

Answer 1

Answer:

i) <POQ= 45°

i) <POQ= 45°ii) <QOR= 60°

i) <POQ= 45°ii) <QOR= 60°iii) <POR= 255°

Hope you find it helpful.

Answer 2

Answer:

Step-by-step explanation:

AC is side of regular hexagon

OC=OE=OB

O is  a center

angle made by side at the center

by a polygon of side n - 2$\pi$/n =360/n

∠AOC= 360/6=60°

∠AOB= 360/8=45°

∠BOC= ∠AOB+∠AOC=60°+ 45°=105°