Question

In the given figure o is the centre of a circular arc and AOB is a straight line find the perimeter of the area of the shaded region
$use\pi = 3.14$
​

Answer 1

Answer:

mark as brainlist

Step-by-step explanation:

Answer 2

$\huge\purple{\mid{\fbox{\tt Hi\:Mate}\mid}}$

$\Large\bold{\underline{\red{Question}}}$

The given figure shows the center of a circular arc and AOB is a straight line. Find the perimeter and the area of the shaded region correct to one decimal place. (Take π=3.142)

$\small\fbox\pink{Answer:61.1cm}$

$\Large\bold{\underline{\red{Answer}}}$

In right angle triangle ACB,

$\fbox\orange{AB ² = AC² + BC²}$

⟹ (12)² + (16)² = 144 + 256 = 400

$AB = \sqrt{400}$

∴ Diameter = 20m

Radius

$= \frac{20}{2} = 10m$

Arc length ACB

$= \frac{1}{2}×2πr$

$=\frac{1}{2}×2×3.142×10$

= $\small\fbox\blue{31.42m}$

Perimeter of shaded region

$=31.42+12+16$

= $\small\fbox\blue{59.42cm}$

Area of shaded region

$= \frac{1}{2} πr² - \frac{1}{2} ×AC×CB$

$= \frac{1}{2}(3.142×10² −12×16)$

$= \frac{1}{2} (314.2−192)$

$=\frac{1}{2} ×122.2$

= $\small\fbox\pink{61.1cm}$

$\Large\color{aqua}Happy\:Learning$

$\Large\fbox\red{Mark\:As\:Brainliest}$