Question

In the given figure O is the centre of circle of radius 5cm. OP perpendicular CD,AB parallel to CD
AB = 6 cm and CD= 8cm. Determine PQ 5

Answer 1

Step-by-step explanation:

Join OA and OC. Since, the perpendicular from the centre of the circle to a chord bisects the chord. Therefore, P and Q are mid- points of AB and CD respectively. ∴ PQ = OP + OQ = (4 + 3) cm = 7 cm.

Answer 2

Answer:

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