Question

in the given figure , 'O' is the centre of circle , PQ is a chord and the tangent PR at P makes an angle of 50° with PQb ,then find angle POQ.​

Answer 1

Answer:

100°

Step-by-step explanation:

∠OPQ = 90° - 50° = 40°

OP = OQ       (Radii of a circle)

⇒ ∠OPQ = ∠OQP = 40°

(Equal opposite sides have equal opposite angles)

∴ ∠POQ = 180° - ∠OPQ - ∠OQP

              = 180° - 40°

              = 100°