In the given figure O is the centre of circle proove XOZ=2(XZY+YXZ)
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In circle C (O, r), ⌢ X Y XY⌢ subtends ∠XOY at the centre O and ∠XZY at a point Z on the remaining part of the circle. By Central Angle theorem ∠XOY = 2 ∠XZY ….(1)
Similarly, ∠YOZ = 2 ∠YXZ …(2) Adding Eqn. (1) & (2)
∠XOY + ∠YOZ = 2 (∠XZY + ∠YXZ) => ∠XOZ = 2 (∠XZY + ∠YXZ)
Hence proved
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