Question

In the given figure, O is the centre of the circle.
AB and BC are two equal chords of the circle,
if ABC = 60°, then OAB is :
(a) 60°
(b) 120°
(d) 90°
(c) 30°​

Answer 1

$\sqrt{oab } = 2\sqrt{abc} \\ \sqrt{oab} = 2 \times 60 \\ \\ \sqrt{oab } = 120$

by using the theorem...(angle in the centre is twice the angle on the remaining circle.)

hope this answer will be helpful

Answer 2

Answer:

answer is 120 is correct