Question

In the given figure, O is the centre of the circle. ABCD is a trapezium in which AB || DC and ∠ADC = 110°. The measure of ∠ACD is equal to:

Answer 1

Answer:

ABCD is a cyclic quadrilateral..

so angle b+ angle D = 180°

angle d = 180°-110°

angle d=70°

AB is diameter

so angle ACB is 90°

angle CAB+ Angle ABC+ Angle BCA =180° (angle sum property

=70°+90°+BAC=180°

angle BAC=20°

angle BAC= angle ACD (interior alternate) (because in trapezium it's parallel)

angle ACD=20°