In the given figure, O is the centre of the circle and AB is the diameter. If ∠ = 90 and OB =
◦
BC, find ∠1.
a) 30
o
b) 45
o
c) 60
o
d) 70
o
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Answer: The measure of ∠1 = 60° , hence answer is c) 60°
Step-by-step explanation:
Given Data:
O is the centre of the circle,
AB is the diameter.
OB = BC
∠C = 90° (assume since not given in question, also we know that diameter subtends 90° angle on any point of the circle.)
To find: ∠1
Refer the attached image (some parts are assumed since detail not mentioned)
Now, in the given circle, OA = OB = OC (since they are radii)
Also, OB = BC (given)
So, in ΔBOC, 0B = BC= OC
⇒ΔBOC is equilateral triangle. (all sides equal)
Therefore all the angles, measure = 60°
Hence ∠1 = 60° (assuming it is one of the angles of ΔBOC, since figure not given)
Attachments:
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