Question

In the given figure, O is the centre of the
circle and angle BDC = 42°. Find the measure of
angle ACB.​

Answer 1

ANSWER

Angle CDB=angle BAC=42°(angles subtended by same chord)

CA is diameter,therefore angle ABC=90°(angle subtended by diameter is 90°)

In triangle CBA ,angle ACB=48°[angle

sum property]

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Answer 2

Answer

48°

Explanation

since ,AC is the diameter .so ∆ADC will be 90°

therefore,

∆ADB = 90-∆BDC

= 90-42

∆ADB = 48°

∆ACB=∆ADB =48°

(angle in same segment are equal)