Question

In the given figure, O is the centre of the circle and BA = AC. If ∠ABC = 60o, find ∠BOC and ∠BDC.

Answer 1

please give the figure bro.........

Answer 2

I will not use angle symbol, directly write the name.

ABC=ACB(isoceles triangle)

BAC+ABC+ACB = 180

BAC+50+50=180

BAC= 80

BOC = BDC = 160

Hope the answer is helpful !!

Good Day !!