Question

In the given figure, O is the centre of the circle and
OBC -50° Calculate (1) ADC AOC​

Answer 1

In the given figure, O is the centre of the circle. Arc ABC subtends an angle of 130° at the centre O. AB is extended upto P. Find ∠PBC.

Answer 2

Step-by-step explanation:

Take any point D on the circumference and join AD and DC .

∴ ∠AOC = 2 × ∠ADC

⇒ ∠ADC = 1/2 × ∠AOC = 1/2 × 130° = 65°

Now, ∠PBC = ∠ADC [exterior angle of cyclic quadrilateral]

⇒ ∠PBC = 65°