Question

In the given figure, O is the centre of the circle
and XOY is a diameter. If XZ is any other chord
of the circle, show that XY > XZ.​

Answer 1

when we take XO=a

then XY equals to 2a

XOZ is a right angle triangle so XZequals to √(a^2+a^2)

2a > √(a^2+a^2)

so,XY > XZ