Question

In the given figure, O is the centre of the circle , Angle CBE = 250

and

Angle DEA = 600

, then find Angle ADB ​

Answer 1

Answer:

(Angle sum property )180° - 60 °+ 25° ( Corresponding oppsite angle)

180 - (60+25)

180 - 85

= 95°

Therefore: Angle ADB = 95°

Answer 2

Answer:

∠ADB = 95°

Step-by-step explanation:

∠CEB = ∠DEA [Vertically opp. angles]

=> ∠CEB = 60°

Now, in △CBE

∠CEB + ∠CBE + ∠ECB = 180° [ASP]

=> ∠ECB = 180° - 85° = 95°

From theorem, angles in the same segment are equal

Therefore, ∠ADB = ∠ECB

=> ∠ADB = 95°