Question

In the given figure o is the centre of the circle angle obc = 50° and AB = AC . Find angle BAC and angle BDC

plz answer fastt.......​

Answer 1

Answer:

Step-by-step explanation:

In triangle BOC,

<OBC= <OCB (OB and OC are the radio of the circle)

<OCB=50˚

<OBC+OCB+<BOC=180

<BOC =180-100

=80

<BAC= 1/2<BOC

BAC =40

BAC+BDC=180(opposites sides of cyclic quadrilateral are supplementary)

BDC= 180-40=140