Question

. In the given figure, O is the centre of the circle, ∠BAO = 68°, AC is the diameter of the circle, then find

∠BCO. urgent ​

Answer 1

Answer:

angle bco is 22 degree

Step-by-step explanation:

as ac is diamter, angle susbstended by two chords touching diameters end they substend 90 degree . so by asp 90 +68 +bco= 180 . hence bco equals 22 degree

Answer 2

Answer: 68°

Step-by-step explanation:

∠BAO = 68°
⇒ ∠ BCO = 68° (Angles in same segment)

Hope this helps.