Question

in the given figure O is the centre of the circle find angle CBD

Answer 1

angle c = 90 ( angle formed in a semi circle is always 90)

angle A = angle B (angle formed by same cord are equal )
angle B = x
angle A + angle B + angle C = 180
x + 2 x = 180 -90
3 x = 90
x = 90/3
x = 30

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Answer 2

Heyy mate ❤✌✌❤

Here's your Answer...

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Given;

AOC =100.

By the theorm,

Angle Substended at the semisircle is half of the angle at the centre.

=> APC = 50°

NOW,

IN Cyclic Quadrileteral ABCP,

We know that In CYCLIC QUADRILETERAL sum of opposite side is 180.

=> APC + ABC = 180

=>ABC = 180 - 50

=> ABC = 130°.

NOW,

ABC + CBD = 180° (LINEAR PAIR)

=> CBD = 180 - 130

=> CBD = 50°
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