in the given figure O is the centre of the circle. find CBD.
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Here we see angle APC is 50° ( half of the angle subtended at the centre.by arc AC)
Therefore Angle ABC = 180°- 50°( 50°+angleABC=180°(sum of opp. angles of cyclic quad is 180°))
let angle CBD =x
therefore
Angle ABC + AngleCBD=180°(linear pair)
50°+ x=180°
x=180°-50°x=130°
Therefre Therefore angle CBD = 130 °
Therefore Angle ABC = 180°- 50°( 50°+angleABC=180°(sum of opp. angles of cyclic quad is 180°))
let angle CBD =x
therefore
Angle ABC + AngleCBD=180°(linear pair)
50°+ x=180°
x=180°-50°x=130°
Therefre Therefore angle CBD = 130 °
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Answer:
Since the acceleration due to gravity is less at equator as compared to that at poles, the weight of the gold will be less at the equator than at the poles. Hence, Amit's friend won't agree with the weight of the gold bought since it would be less than what he is expecting.
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