In the given figure O is the centre of the circle. if Angle ABD =35 and angle BAC =70 find angle ACB
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∠ACB = 55° if O is the centre of the circle and Angle ABD =35 and angle BAC =70
Step-by-step explanation:
∠ADB = ∠ACB as both angles from same chord on same side
O lies on BD
Hence BD is Diameter
and∠DAB = 90°
in Δ ABD
∠DAB + ∠ADB + ∠ABD = 180°
=> 90° + ∠ADB + 35° = 180°
=> ∠ADB = 55°
∠ADB = ∠ACB
=> ∠ACB = 55°
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In the figure O is the centre of the circle
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