Question

In the given figure O is the centre of the circle. if Angle ABD =35 and angle BAC =70 find angle ACB​

Answer 1

∠ACB =   55° if O is the centre of the circle and Angle ABD =35 and angle BAC =70

Step-by-step explanation:

∠ADB = ∠ACB     as both angles from same chord on same side

O lies on BD

Hence BD is Diameter

and∠DAB = 90°  

in Δ ABD

∠DAB  + ∠ADB + ∠ABD = 180°

=> 90° + ∠ADB + 35°  = 180°

=> ∠ADB = 55°

∠ADB = ∠ACB  

=> ∠ACB =   55°

Learn More:

In the figure O is the centre of the circle

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Answer 2

Answer:

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