in the given figure O is the centre of the circle if angle AOC equals to 130 degree then find angle abc according to theorem
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3
∠AOC=130°
∠ABC = 1/2∠AOC (angle substended by an arc is half the angle substended by an arc at the centre )
=130/2
=65°
∴∠ABC=65°
Answered by
2
acc to your question angle ABC will be 50degree
discover99:
no but ans given is 115
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