Question

in the given figure o is the centre of the circle if OA=17 cm AB =30 and OD is perpendicular to AB then find CD​​

Answer 1

Step-by-step explanation:

For the triangle ACO,

(AO )2 =(OC )2 +(AC )2

OC= √(OA 2 −AC 2)

OC= 17 2−15 2

OC=8cm

CD=OD−OC

CD=17cm−8cm

CD=9cm