Question

In the given figure O is the centre of the circle if ∠OAB = 40° and C is a point on the
circle, then find ∠ACB

Answer 1

Step-by-step explanation:

Hope this is ur answer....

Answer 2

Answer:

∵OA=OB (radius of circle)

∴∠OAB=∠OBA (angles opposite to equal sites)

∠OBA=40°

In right angled ΔOAB

∠OAB+∠OBA+∠AOB=180°

40° + 40° +∠AOB=180°

∠AOB=180°-80°

∠AOB=100°

We know that

∠ACB= 1/2 ∠ A B C

= 1/2 ×100° = 50°