In the given figure, O is the centre of the circle. If OD LAC, OB = 5 cm, OD=3 cm, then length of BD is:
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since,we know that OD is perpendicular to AC.
therefore, In right triangle ODB,
(BD) ²=(OD)²+(OB) ²
BD²=(3) ²+(5) ²
BD²=9+25
BD²=34cm
BD=√34
BD=2√17cm
therefore, Required value of BD is 2√17 cm.
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