Question

in the given figure o is the centre of the circle PA amd PB are tangent to the ciecle .find angle of AQB

Answer 1

Answer:

(I think you meant find angle AOB?)

Angle PAO = Angle PBO = 90 ( Tangents are perpendicular)

In quad. PAOB,

Sum of all angles = 360

Angle PAO + Angle PBO + Angle APB + Angle AOB = 360

180 + Angle APB + Angle AOB = 360

Angle APB + Angle AOB = 180

Angle AOB = 2(Angle APB)

Let Angle APB = x & Angle AOB = 2x

3x = 180

x = 60

So, angle AOB = 120