In the given figure, O is the centre of the circle. PQ is a chord of the circle and R is
any point on the circle. If ∠PRQ = l and ∠OPQ = m, then find l + m.
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∠POQ = 2∠PRQ
⇒ ∠POQ = 2l
In △PQO, OP = OQ = r
⇒ ∠OQP = ∠OPQ = m
Also, ∠OPQ + ∠OQP + ∠POQ = 180°
⇒ m + m + 2l = 180°
⇒ 2m + 2l = 180°
⇒ 2(l + m) = 180°
⇒ l + m = 90°
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