Question

in the given figure o is the centre of the circle. the distance between p and Q is a 4cm find the angle ROQ​

Answer 1

Step-by-step explanation:

let angle RQO = x

we have angle POQ = 80°

angle ROQ = 120°

therefore, angle POR = 160° ------ (1)

Now in ∆POQ,

PO = OQ ( radii of same circle)

therefore, angle P = angle Q = 50° (isosceles ∆)

we know that,

angle POR = 2( angle PQR) ------> (circle property)

160° = 2(50 + x)

80° = 50 + x

So, x = 30°

then we can conclude that,

the angle RQO = x= 30°