Question

in the given figure O is the centre of the circle then find angle CBD.......please quick​

Answer 1

Answer:

°.° ABCP is a cyclic quadrilateral

.•. angle APC = angle CBD

angle APC = ½angle AOC

=> angle APC = 50°

•.• angle APC = angle CBD

=> angle CBD = 50°

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Answer 2

$ABCP~is~a~cyclic~quadrilateral$

$angle~APC=~angle~CBD$

$angle~APC=~\frac{1}{2} ~angle~AOC$

$=>~angle~APC=50°$

$angle~APC=~angle~CBD$

$=>~CBD=~50°$