Question

in the given figure O is the centre of the circle with radius 5 centimetre and op perpendicular to CD, OQ perpendicular to AB and AB parallel to CD AB equal to 6 cm and CD is equal to 8 cm determine PQ

please answer this question fast​

Answer 1

Answer:

..OQ=v5^2-3^2 =v 25-9=v16=4

op=V5^2-4^2 =v 25-16 =v9=3

0Q+op=P Q

P Q = 4+3=7cm

Answer 2

Answer:

Step-by-step explanation: