Question

in the given figure, O is the centre of the circle with radius 14cm. find the area of the shaded portion..​

Answer 1

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Area of semi circle = πr^2/2

Radius of the circle = 14 cm

so , the area of the semi circle =

1/2 X 22/7 X 14 X 14

= 4312/14

= 308 cm^2

Area of the big triangle = 1/2 X base X height

= 1/2 X 28 X 14

= 392/2

= 196 cm^2

so, the area of shaded part on the upper part of the circle =

= 308 cm^2 - 196 cm^2

= 112 cm^2

similarly when coming to the bottom part of the triangle we have a circle of radius 7 cm

so the area of the circle = πr^2

= 22/7 X 7 X 7

= 154 cm^2

So the total shaded part =

Area of shaded part in upper part of the circle + Area of shaded part in lower part of the circle.

= 112 cm^2 + 154 cm^2

= 266 cm^2

So, therefore area of shaded part is 266 cm^2

Answer 2

Answer:

$\color{red}{\huge{\fbox{\fbox{\bigstar{\mathfrak{\color{blue}{..!!!Hello\: Mate!!...}}}}}}}$

Area of semi circle = πr^2/2

Radius of the circle = 14 cm

so , the area of the semi circle =

1/2 X 22/7 X 14 X 14

= 4312/14

= 308 cm^2

Area of the big triangle = 1/2 X base X height

= 1/2 X 28 X 14

= 392/2

= 196 cm^2

so, the area of shaded part on the upper part of the circle =

= 308 cm^2 - 196 cm^2

= 112 cm^2

similarly when coming to the bottom part of the triangle we have a circle of radius 7 cm

so the area of the circle = πr^2

= 22/7 X 7 X 7

= 154 cm^2

So the total shaded part =

Area of shaded part in upper part of the circle + Area of shaded part in lower part of the circle.

= 112 cm^2 + 154 cm^2

= 266 cm^2

So, therefore area of shaded part is 266 cm^2