Question

in the given figure O is the centre of the circle with its equal to 24 cm is equal to 7 cm Angle B equal to 90 degree find the area of the shaded region

Answer 1

In circle ,
CB is diameter
so, circle divided into two equal parts that is semi circle.
Angle CAB in semicircle
So it is right angle
then , In Triangle BAC ,
Angle BAC =90°

${BC}^{2} = 576 + 49$

${BC}^{2} = {AC}^{2}+ {AB}^{2}$
......By Pythagoras Theoram

${BC}^{2} = {24}^{2} + {7}^{2}$

Answer 2

Answer:

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