in the given figure o is the point in interior angle QPR oa is perdendicular to PQ and OT perpendicular to pr if angle qpr is 60°find tos
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tos =360-90+90+60=360-240=120
radheygaikwad6pcsi0f:
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Answered by
4
Angle sum of quadrilateral = 360
<PTO+<STP+<PSO+<TOS = 360
90+60+90+<TOS =360
240+<TOS = 360
<TOS = 360-240
= 120°
<PTO+<STP+<PSO+<TOS = 360
90+60+90+<TOS =360
240+<TOS = 360
<TOS = 360-240
= 120°
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