Question

In the given figure ,o is the point inside triangle PQR is a right angled triangle .Find the area of PQRO

Answer 1

Answer:

This is true answer........

Answer 2

in triangle pqr

from Pythagoras therom

6^2+8^2=(pr)^2

(pr)^2=36 +64=100

pr=10

in triangle pqr

from rule=√s(s-a)(s-b)(s-c)

s=perimeter/2

a, b,c are side of triangle

s= 24+26/2

Area of triangle pqr=√30(30-26)(30-24)(30-10)

√30×4×6×20

=√14400

=120cm^2

in triangle por

Area=1/2×6×8

=24cm^2

Now,acc.to question

area of pqro=area of triangle (pqr-por)

=120-24

=96cm^2 answer