In the given figure oà and OB are opposite rays and ZAOC + ZBOD=90° then
find the value of ZCOD.
D
С
B
O
A
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Given : OA and OB are opposite rays and ∠AOC + ∠BOD= 90°
To find : ∠COD
Solution:
OA & OB are opposite rays
hence AB is straight line
∠AOC + ∠COD + ∠BOD = 180°
=> ∠AOC + ∠BOD + ∠COD = 180°
∠AOC + ∠BOD = 90° given
=> 90° + ∠COD = 180°
=> ∠COD = 90°
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