Question

In the given figure OA_OB_21cm and angle AOB _120 The area of sector OAYB is
​

Answer 1

Answer:

The area of segment is given as area of sector -area of triangle

Radius of circle is 21cm

The angle at center is 120

∘

Area of sector is

360

x

×π×r×r

=

360

120

×

7

22

×21×21

=22×21=462cm

2

Area of triangle

2

1

absinθ

=

2

1

×21×21sin120

=

4

441

3

=190.953

Area of segment is =462−190.953=271.047cm

2

Answer 2

Answer:

Step-by-step explanation:

The area of segment is given as area of sector -area of triangle

Radius of circle is 21cm

The angle at center is 120

∘

Area of sector is

360

x

×π×r×r

=

360

120

×

7

22

×21×21

=22×21=462cm

2

Area of triangle

2

1

absinθ

=

2

1

×21×21sin120

=

4

441

3

=190.953

Area of segment is =462−190.953=271.047cm

2