Question

in the given figure, OA=OB and OC=OD show that
i) ∆ AOC is congruent to ∆BOD
ii) AC II BD​

Answer 1

Answer:

2

Explanation:

it is best answer for this question

Answer 2

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ANSWER

Given ∠AOB=∠COD

∠AOB−∠COB=∠COD−∠COB

∴∠AOC=∠DOB

In ΔAOC and ΔDOB

i)OA=OB(Given)

ii)OC=∠OD (Given)

iii)∠AOC=∠DOB (Proved above)

∴ΔAOC≅∠DOB

(SAS Axiom)

∴AC=BD

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