Question

In the given figure .∆OAB=110° and ∆BCD=130°,∆ABC=x.find the value of x​

Answer 1

Answer:

angle x = 60 degree

refer to the attachment for the explanation

Answer 2

Answer:

The value of x is $60^0$

Step-by-step explanation:

Given:

$<OAB=110^0$

$<BCD=130^0$

We need to find the $<ABC$

If a line is drawn parallel to OA and CD meeting the point B be XY line

Then since OA is parallel to XB we know that adjacent angles will make $180^0$

So we get as

$110+<XBA=180\\\\<XBA=70^0$

Similarly with CD and BY we get as

$130+<CBY=180\\\\<CBY=50^0$

The line makes an angle of $180^0$ at B so we get as

$<XBA+<CBY+<ABC=180\\\\70+50+x=180\\\\x=60^0$