Question

In the given figure OABC is a rhombus whose vertices lie on circle of radius 10cm, then area of rhombus is (use √3=1.7)​

Answer 1

AREA of rhombus = (d× d') /2

d=BO=10

let PO=x

so, AP^2=100-X^2

AP^2=100-(10-X)^2

100-X^2=100-(10-X)^2

100-X^2=100-100-x^2+20x

x=4

AP^2=100-16=84

AP=√84

AC=d'=2√84

AREA=10√84