In the given figure, OACB is a quadrant of a circle with centre 0 and radius 3.5 cm. If OD = 2 cm, find the area of the shaded region.
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22
Hey. .
radius or Base of triangle DOB is 3.5 cm
Od=2 cm
And area of whole quadrant is 1/4 ×22/7×3.5×3.5 is 9.625
So for shaded region subtract area of triangle DOB from 9.625
=1/2 ×2×3.5
=3.5
So area is 9.625-3.5
=6.125 cm^2
Please mark as brainiest. .I literally spent 15 min in this
radius or Base of triangle DOB is 3.5 cm
Od=2 cm
And area of whole quadrant is 1/4 ×22/7×3.5×3.5 is 9.625
So for shaded region subtract area of triangle DOB from 9.625
=1/2 ×2×3.5
=3.5
So area is 9.625-3.5
=6.125 cm^2
Please mark as brainiest. .I literally spent 15 min in this
Answered by
28
Radius of quadrant OAB = 3.5 cm
Angle of sector = 90°
Area of shaded region
= Area of sector OACB - Area of ∆OBD
= ( 90/360) ×22/7×3.5×3.5-[1/2 ×2×3.5 ]
= 77/8 - 35/10
= 77/8 -7/2
= ( 77 - 28 )/8
= 49/8
= 6.125 cm²
•••••
Angle of sector = 90°
Area of shaded region
= Area of sector OACB - Area of ∆OBD
= ( 90/360) ×22/7×3.5×3.5-[1/2 ×2×3.5 ]
= 77/8 - 35/10
= 77/8 -7/2
= ( 77 - 28 )/8
= 49/8
= 6.125 cm²
•••••
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