Question

in the given figure. OD chord AB OA = 13, AB=24, OD=?​

Answer 1

Answer:

Perpendicular drawn from centre of a circle to chord bisects the chord.

AC=BC=12cm

And ∠OCB=90  

∘

 

Thus, triangle OCB is a right angled triangle

OB=13cm.

Therefore by Pythagoras theorem

OB  

2

=OC  

2

+BC  

2

 

OC  

2

=OB  

2

−BC  

2

 

OC=  

13  

2

−12  

2

 

​  

 

OC=5cm