Question

In the given figure, OE and OF bisects <AOC and <COB respectively and OE parallel OF. Show that points A, O , B are collinear.​

Answer 1

hope it's helpful

hello what's your age

and

your name

Answer 2

Step-by-step explanation:

Since OE bisects ∠AOC

So, ∠AOE=∠EOC

∠EOC=

2

1

∠AOC --- (i)

also ,OF bisects ∠COB

∠COF=∠BOF

∠COF=

2

1

∠BOC ----- (ii)

Now, OE⊥OF

∠EOF=90

∘

∠EOC+∠COF=90

∘

2

1

∠AOC+

2

1

∠BOC=90 °

from (i) and (ii)

∠AOC+∠BOC=180 °

AOB is straight line

Prove.