In the given figure, OEB = 75°, OBE = 55° and OCD = 100%. Then ODC=?
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Given :- In the given figure, ∠OAB is equal to 75°, ∠OBA is equal to 55° and ∠OCD is equal to 100°. Then ∠ODC is equal to ?
Solution :-
In ∆OAB, we have,
→ ∠OAB + ∠OBA + ∠AOB = 180° (By Angle sum Property.) → 75° + 55°+ ∠AOB = 180°
→ 130° + ∠AOB = 180°
→ ∠AOB = 180° - 130°
→ ∠AOB = 50°
now, as we can see that,
→ ∠COD = ∠AOB = 50° (vertically opposite Angles.)
In ∆OCD, we have,
→ ∠COD + ∠OCD + ∠ODC = 180° (By Angle sum Property.)
→ 50° + 100° + ∠ODC = 180°
→ 150° + ∠ODC = 180°
→ ∠ODC = 180° - 150°
→ ∠ODC = 30° (Ans.)
Learn more :-
In ABC, AD is angle bisector,
angle BAC = 111 and AB+BD=AC find the value of angle ACB=?
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