In the given figure, OP bisects angle BOC and OQ bisects angle AOC. Show that angle POQ=90
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Answered by
11
aoc=90°
BOC=90
1/2BOC =45
1/2AOC=45
QOP= 1/2BOC+1/2AOC
QOP=45+45
QOP=90°
BOC=90
1/2BOC =45
1/2AOC=45
QOP= 1/2BOC+1/2AOC
QOP=45+45
QOP=90°
Answered by
9
heya it's Aastha...
AOB is straight line
so,
◆AOC =90
◆BOC = 90.
According to question,
OP bisects angle BOC and OQ bisects angle AOC.
Since ,
QOC = 45
POC =45
then,
POQ= 90.
hence proved.....
I hope it help you
AOB is straight line
so,
◆AOC =90
◆BOC = 90.
According to question,
OP bisects angle BOC and OQ bisects angle AOC.
Since ,
QOC = 45
POC =45
then,
POQ= 90.
hence proved.....
I hope it help you
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