Question

In the given figure, OP is the bisector of ∠LOM . Find the length of PM.

Answer 1

Answer:

In △s APB and ABQ, we have

∠APB=∠AQB (Each 90 ∘ )

∠PAB=∠QAB (AB bisect ∠PAQ)

AB=BA (common)

Therefore, △APB≅△ABQ

(AAS)⇒ BP=BQ (cpct)

Hence, B is equidistant from the anus of ∠A

Answer 2

Step-by-step explanation:

this question's answer is PM = 4cm